Grade 12Algebra
Solve the limits question in attachments ..........................................................................
Solve the limits question in attachments ..........................................................................
1 Answer
Aditya Gupta
put y= arcsinx or x= siny so that y tends to pi/4.
numerator becomes arccos(2sinyroot(1 – sin^2y))=arccos(2sinycosy)=arccos(sin2y)= pi/2 – arcsin(sin2y)= pi/2 – 2y
so limit becomes [pi/2 – 2y]/(siny – sinpi/4)= [pi – 4y]/4sin(y – pi/4)/2cos(y+pi/4)/2
now this can be easily evaluated by putting pi – 4y= z :)
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