Arun8 Years agoFind nth termTn = 1/(5n-4)(5n +1) = 1/5(5n-4) - 1/5(5n+1) = 1/5 [1/(5n-4) - 1/(5n+1)] Now Put value n = 1 ,2 ,3......n And then add Only two terms will remain Sn = 1/5 [1 - 1/(5n +1)] RegardsArun (askIITians forum expert)