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Solve the following pair of linear equations by the substitution method 0.2x + 0.3y = 1.3 0.4x + 0.5y = 2.3
Dear StudentGiven,0.2x + 0.3y = 1.3and0.4x + 0.5y = 2.3are the two equations.From 1st equation,we get,x = (1.3- 0.3y)/0.2 _________________(1)Now,substitute the value of x in the given second equation to get,0.4(1.3-0.3y)/0.2 + 0.5y = 2.3⇒2(1.3 – 0.3y) + 0.5y = 2.3⇒ 2.6 - 0.6y + 0.5y = 2.3⇒ 2.6 – 0.1 y = 2.3⇒ 0.1 y = 0.3⇒ y = 3Now, substitute the value of y in equation (1),we get,x = (1.3-0.3(3))/0.2 = (1.3-0.9)/0.2 = 0.4/0.2 = 2Therefore, x = 2 and y = 3 is required solution.Thanks
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