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`        Solve the following inequations -(a) (x -1)( x2 – x – 2 )1/2 = 0 (b)( 2 – x – x2 )1/2=  x – 4`
5 years ago

```							(x-1)(x2-x-2)1/2=0=>either x-1=0 or(x2-x-1)1/2=0if x-1=0 then x=1and if (x2-x-1)1/2 =0 thenx2-x-1=0 and x2-x-1>/0=> (x-2)(x+1)=0 and(x-2)(x+1)>/0=>x=2,-1 and x=-1 or x=2so we ox=2 and -1so total values of x=-1,2,1Thanks & RegardsRinkoo GuptaAskIITians Faculty
```
5 years ago IIT Delhi
174 Points
```							(a) x=1, -1, 2 are satisfying the functionbut x2–x –2>=0so x belongs to (-infinite ,-1]U[2,infinte)so x=-1 and x=2 are solutions(b)-x2–x +2>=0-2 and 1 satisfies the equation so x belong to [-2,1]squaring both sides2 – x – x2=x2-8x+16=>2x2-7x+14=0 D<0 so no solutionSher Mohammadfaculty askiitians
```
5 years ago
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