Last Activity: 3 Years ago
Dear Student
From the question it is given that,
We know that, the sum of angles of a triangle is 180o
Let base angle be b
Then,
= b + b + 40o = 180o
= 2b + 40o = 180o
By transposing 40 from LHS to RHS it becomes -40
= 2b = 180–40
= 2b = 140
Now,
Divide both the side by 2
= 2b/2 = 140/2
= b = 70o
Hence, 70ois the base angle of an isosceles triangle.
Thanks
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