Solve the equation (x^2+3x+1)(x^2+3x-3)>=5
aishvardhan , 11 Years ago
Grade
Algebra> Solve the equation (x^2+3x+1)(x^2+3x-3)>=...
1 Answers
bharat bajaj
Take y = x^2 + 3x
Now, (y+1)(y-3)>=5
y^2 -2y -8 >=0
Now, (y+1)(y-3)>=5
y^2 -2y -8 >=0
(y+2)(y-4)>=0
Now y = (-inf,-2) (4,inf)
Now y = (-inf,-2) (4,inf)
x^2 + 3x <= -2
(x+2)(x+1)<=0
x belongs from (-1,-2)
x^2 + 3x >=4
(x+4)(x-1)>=0
Hence, x= (-inf,-4) (1,inf)
These are the solutions
THanks
(x+2)(x+1)<=0
x belongs from (-1,-2)
x^2 + 3x >=4
(x+4)(x-1)>=0
Hence, x= (-inf,-4) (1,inf)
These are the solutions
THanks
Bharat Bajaj
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