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SOLVE THE EQUATION AND FIND THE VALUE OF X FOR THE FOLLOWING EQUATION (12x−1)(4x−1)(3x−1)(6x−1)=5

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4 years ago

Vikas TU
14146 Points
```							(12x−1)(4x−1)(3x−1)(6x−1)=5mukltiplying each term with each other we get the final eqn. as:  864x4-720x3+210x2-25x-4 = 0From remainder theorem,x = 0.5 satifies it.Hence (x – ½ ) is the factor of the bi – quadratic polynomial.On dividing by the divisor (x – 1/2) we get,   432x3-144x2+33x+4 = 0 Now from remainder theorem, x = -1/12 satifies it.Therfore on dividing the cubic eqn. by (12x + 1) we get the quadratic as:36x2-15x+4 = 0Final result can be written as: => (12x+1) ( x- 1/2) (36x2-15x+4) as 36x2-15x+4 has the discriminantt is less than zero.
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4 years ago
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