solve mod x^2 +4x +3=x+1.

Question

sanju Ramanathan · Answer

x 2 + 4x + 3 = x +1 x 2 + 3x +x + 3 = x + 1 (splitting the middle term) x(x+3) 1(x+3) = x + 1 (x+1)(x+3) = x+1 x+3 = x+1/x+1 x+3 = 1 x= 1-3= -2

Akshita Goyal · Answer

@sakthi meena no your answer is wrong because it is mod before the term.

Shubham Swastik Behera · Answer

|x 2 +4x+3|=x+1, Now, the LHS changes at different values of x. x 2 +4x+3=(x+3)(x+1)=+ve for x -1 ...(i) while it is -ve for x between -3 and -1 ...(ii) So, for (i) we have x 2 +4x+3=x+1 on solving which we get x= -2 or -1 but we cannot take -2 as it is inbetween -3 and -1 i.e. not satisfying range of x set in (i) whereas for (ii) we have -(x 2 +4x+3)=x+1 on solving which we get x= -4 or -1 but we cannot take -4 as it doesnot lie in the range set in (ii) so our only solution is x=-1.

Shubham Swastik Behera · Answer

correction!! x 2 +4x+3=(x+3)(x+1)=+ve for x -1. cheers!!

Shubham Swastik Behera · Answer

Something is wrong with the greater than and less than symbol. I’m writing it in words: x 2 +4x+3=(x+3)(x+1)=+ve for when x is outside (-3,-1) i.e. less than -3 and greater than -1. Cheers!!

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solve mod x^2 +4x +3=x+1.

solve mod x^2 +4x +3=x+1.

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