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Grade: 8
        
Sir 
Pls solve this quadratic eqn and find the roots.
2 years ago

Answers : (1)

Aniket Pratap Singh
21 Points
							
ax+ bx+c=0
x2 + (b/a) x + (c/a) = 0      (Dividing by a)
x2 + 2 * (b/2a) * x + (c/a) = 0     (Dividing and multiplying by 2 in the second term of the equation.)
x+2 * (b/2a) * x + (b/2a)-(b/2a)+ (c/a) = 0        (Making the eqation perfect square by adding and substracting (b/2a))
[ x + (b/2a) ] – b2/4a2 + c/a = 0
[ x + (b/2a)]= b2/4a – c/a 
[ x + (b/2a)]= (b- 4ac) / 4a
[ x + (b/2a)] =+-[ (b2 – 4ac) / 4a2½
[ x + (b/2a)] = ± [(b2 -4ac)1/2 ] / (2a)
x = -b/2a +-(b2 -4ac)½ /2a
x = [-b ± (b-4ac)1/2 ] / 2a   
 
Therefore the anser is (d) None of these
2 years ago
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