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`        Sir Pls solve this quadratic eqn and find the roots.`
2 years ago

Aniket Pratap Singh
21 Points
```							ax2 + bx+c=0x2 + (b/a) x + (c/a) = 0      (Dividing by a)x2 + 2 * (b/2a) * x + (c/a) = 0     (Dividing and multiplying by 2 in the second term of the equation.)x2 +2 * (b/2a) * x + (b/2a)2 -(b/2a)2 + (c/a) = 0        (Making the eqation perfect square by adding and substracting (b/2a)2 )[ x + (b/2a) ]2  – b2/4a2 + c/a = 0[ x + (b/2a)]2 = b2/4a – c/a [ x + (b/2a)]2 = (b2 - 4ac) / 4a2 [ x + (b/2a)] =+-[ (b2 – 4ac) / 4a2] ½[ x + (b/2a)] = ± [(b2 -4ac)1/2 ] / (2a)x = -b/2a +-(b2 -4ac)½ /2ax = [-b ± (b2 -4ac)1/2 ] / 2a    Therefore the anser is (d) None of these
```
2 years ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions