sir please solve this question
bollusrinivas , 9 Years ago
Grade 12
Algebra> sir please solve this question
4 Answers
PRAPULPODISHETTI
Last Activity: 9 Years ago
13 guests in the party can be divided inti 2 groups of 8and5 in 13c8 or 13c5.
The first group of 8 guests can be arranged around at one table in 7! ways.
The second group of 5 guests can be arranged around at one table in 4! ways.
So,
The number of arrangements is,
=(13!/5!8!)*(4!)*(7!)
=13!/40 is the answer.
PRAPULPODISHETTI
Last Activity: 9 Years ago
13!/40 value is equlas to 15,56,75,520.
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Last Activity: 9 Years ago
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PRAPULPODISHETTI
Last Activity: 9 Years ago
We can arrange the guests 15,56,75,520 in this ways.
its equals to (13!/40)
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