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Grade 12Algebra

sir please solve this question

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Profile image of bollusrinivas
11 Years agoGrade 12
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4 Answers

Profile image of PRAPULPODISHETTI
11 Years ago
13 guests  in the party can be divided inti 2 groups of 8and5 in 13c8 or 13c5.
The first group of 8 guests can be arranged  around  at one table in 7! ways.
The second group of 5 guests can be arranged  around  at one table in 4! ways.
So,
The number of arrangements is,
=(13!/5!8!)*(4!)*(7!)
=13!/40 is the answer.
 
Profile image of PRAPULPODISHETTI
11 Years ago
13!/40 value is equlas to 15,56,75,520.
Profile image of pkjsdfkjsdfb
11 Years ago
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Profile image of PRAPULPODISHETTI
11 Years ago
We can arrange the guests 15,56,75,520 in this ways.
its equals to (13!/40)