Sir please explain me both the questions above....This question is from topic sets...
Sir please explain me both the questions above....
This question is from topic sets...
deepak , 7 Years ago
Grade 12th pass
Algebra> Sir please explain me both the questions ...
1 Answers
Arun
n(A) = 40% of 10,000 = 4,000
n(B) = 20% of 10,000 = 2,000
n(C) = 10% of 10,000 = 1,000
n (A
B) = 5% of 10,000 = 500
n (B C) = 3% of 10,000 = 300
n(C A) = 4% of 10,000 = 400,
n(A B C) = 2% of 10,000 = 200
We want to find n(A only) = n(A) – [n(A B) + n(A C)] + n(A BC)=
n(A only) = 4000 – [500 + 400] + 200 = 4000 – 700 = 3300
Similarly, n(B only) = n(B) – [n(A B) + n(B C)] + n(A B C)
n(B only) = 2000 - [500+300]+200 = 1400
n(none of A, B and C) = 10,000 - [n(A)+n(B) + n(C) - n (A B) - n(B C) - n (C A) + n(AB C)]
n(none of A, B and C) = 10,000 - [4000+2000+1000 - 500-300-400 + 200]
n(none of A, B and C) = 4000
Approved Last Activity: 7 Years ago
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