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Grade: 12th pass

                        

Sir please explain me both the questions above.... This question is from topic sets...

2 years ago

Answers : (1)

Arun
24742 Points
							
n(A) = 40% of 10,000 = 4,000
n(B) = 20% of 10,000 = 2,000
n(C) = 10% of 10,000 = 1,000
n (A\tiny \cap B) = 5% of 10,000 = 500
n (B\tiny \cap C) = 3% of 10,000 = 300
n(C\tiny \cap A) = 4% of 10,000 = 400,
n(A\tiny \cap B\tiny \cap C) = 2% of 10,000 = 200
We want to find n(A  only) = n(A)  –  [n(A\tiny \cap B) + n(A\tiny \cap C)] + n(A\tiny \cap B\tiny \capC)=
 n(A  only) = 4000  –  [500 + 400] + 200 = 4000 –  700 = 3300
 
Similarly, n(B only) = n(B)  –  [n(A \tiny \cap B) + n(B\tiny \cap C)] + n(A \tiny \cap B \tiny \capC)
n(B only)  = 2000 - [500+300]+200 = 1400
 
n(none of A, B and C) = 10,000 - [n(A)+n(B) + n(C) - n (A \tiny \cap B) - n(B\tiny \cap C) - n (C\tiny \cap A) + n(A\tiny \capB\tiny \cap C)]
n(none of A, B and C) = 10,000 - [4000+2000+1000 - 500-300-400 + 200]
n(none of A, B and C) = 4000
2 years ago
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