Grade Select GradeAlgebra
Sir how to solve the problem in attachment?...............................
Sir how to solve the problem in attachment?...............................
1 Answer
Ajay
Put x2+2 =y the equation reduces to
y2-6xy+8x2=0
(y-4x)(y-2x)=0
This will give two quadratic equations in x which can now be easily solved
x2-4x+2= 0 and x2-2x+2
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