badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: Select Grade

                        

Sir can you tell me the solution of this complex number question in the attachment? The answer is A,D

Sir can you tell me the solution of this complex number question in the attachment? The answer is A,D

4 years ago

Answers : (2)

Vikas TU
14149 Points
							
put z1 = x1 +iy1
and'z2 = x2 + iy2
simple and also thiss is given as:
(x1)^2 + (y1)^2 = (x2)^2 + (y2)^2.
Us ethis info.
4 years ago
mycroft holmes
272 Points
							
Several ways to approach this:
 
  1. Write z = \frac{z_1+z_2}{z_1-z_2} = \frac{1 + \alpha}{1 - \alpha} where \alpha = \frac{z_2}{z_1}
So 
 
\overline {z} = \frac{1+\overline {\alpha} } {1-\overline {\alpha} } = \frac{1+\frac{1} {\alpha} } {1- \frac{1} {\alpha}} 
 
since |\alpha| =1 \Rightarrow \overline{\alpha} = \frac{1}\alpha
 
Hence \overline{z} = \frac{1+\alpha}{\alpha-1} = -z
 
So either z is purely imaginary or z=0. (z=0 is possible when z1=-z2 which is permitted with the restrictions mentioned in the problem)
 
 
4 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details