Harshit Singh
Last Activity: 3 Years ago
Dear Student
25 can be written as = 5 × 5
= 52
103 can be written as = 103
= (5 × 2)3
= 53 × 23
We have,
= (52 × 52 × t8)/ (53 × 23 × t4)
= (52 + 2 × t8)/ (53 × 23 × t4) ... [∵am × an = am + n]
= (54 × t8)/ (53 × 23 × t4)
= (54 – 3 × t8 – 4)/ 23 ... [∵am ÷ an= am – n]
= (5 × t4)/ (2 × 2 × 2)
= (5 t4)/ 8
Thanks