show that area of equilateral triangle inside a circle x^2+y^2+2gx+2fy+c=0 is 3√3/4r^2

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Venky · Answer

we know area of equilateral triangle is (root3)/4)*a^2 so cos@ =(a/2)/r then a=root3 * radius of circle so area is 3root3/4 r^2

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show that area of equilateral triangle inside a circle x^2+y^2+2gx+2fy+c=0 is 3√3/4r^2

show that area of equilateral triangle inside a circle x^2+y^2+2gx+2fy+c=0 is 3√3/4r^2

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show that area of equilateral triangle inside a circle x^2+y^2+2gx+2fy+c=0 is 3√3/4r^2

show that area of equilateral triangle inside a circle x^2+y^2+2gx+2fy+c=0 is 3√3/4r^2

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