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sequences and series question from special series find the sum to n terms n 2 +2

 
sequences and series question from special series
find the sum to n terms n2+2 
 

Grade:11

1 Answers

BALAJI ANDALAMALA
askIITians Faculty 78 Points
5 years ago
\sum_{n=1}^{n}(n^2+2) = \sum_{n=1}^{n}n^2+\sum_{n=1}^{n}2
= \frac{n(n+1)(2n+1)}{6}+2n
= \frac{n(2n^2+3n+13)}{6}

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