roots of the equation x 2 +px+q=0 are 1 and 2. Roots of the equation qx 2 -px+1=0 must be? (a)1/2 and 1 (b)1/2 and -1 (c)-1/2 and -1 (d)-1/2 and 1

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Khimraj · Answer

roots of equation x 2 +px+q =0 are 1 and 2. sum of roots of equation = -p = 1+2 =3 So p = -3 product of roots of equation = q = 1*2 =2 so q= 2 Then equation qx 2 -px +1 =0 becomes 2x 2 + 3x+1 =0 (2x+1)(x+1) = 0 So roots are x = -1/2 and x= -1. Hope it clears. If you like answer then please approve it.

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roots of the equation x 2 +px+q=0 are 1 and 2. Roots of the equation qx 2 -px+1=0 must be? (a)1/2 and 1 (b)1/2 and -1 (c)-1/2 and -1 (d)-1/2 and 1

roots of the equation x²+px+q=0 are 1 and 2. Roots of the equation qx²-px+1=0 must be?
(a)1/2 and 1
(b)1/2 and -1
(c)-1/2 and -1
(d)-1/2 and 1

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roots of the equation x 2 +px+q=0 are 1 and 2. Roots of the equation qx 2 -px+1=0 must be? (a)1/2 and 1 (b)1/2 and -1 (c)-1/2 and -1 (d)-1/2 and 1

roots of the equation x2+px+q=0 are 1 and 2. Roots of the equation qx2-px+1=0 must be?(a)1/2 and 1(b)1/2 and -1(c)-1/2 and -1(d)-1/2 and 1

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roots of the equation x²+px+q=0 are 1 and 2. Roots of the equation qx²-px+1=0 must be?
(a)1/2 and 1
(b)1/2 and -1
(c)-1/2 and -1
(d)-1/2 and 1