AlgebraQuestion number 20 can I get the solution...............,................ 10shivam.m 6 Years agoGrade
Vikas TUApproved Tutor Answer6 Years agoDear student Z= x+iy mag of 2z-i = (2(x+iy) -i )2x + 2iy -i => sqrt (4x^2 + (2y-1)^2 )mag of z+1 = sqrt((x+1)^2 + y^2) The vlue of k must be equal to 2 , to cancel the non linear term , to make it straight line.Good luck
tarang pandey6 Years ago Z= x+iy mag of 2z-i = (2(x+iy) -i )2x + 2iy -i => sqrt (4x^2 + (2y-1)^2 )mag of z+1 = sqrt((x+1)^2 + y^2) Z= x+iy mag of 2z-i = (2(x+iy) -i )2x + 2iy -i => sqrt (4x^2 + (2y-1)^2 )mag of z+1 = sqrt((x+1)^2 + y^2) Z= x+iy mag of 2z-i = (2(x+iy) -i )2x + 2iy -i => sqrt (4x^2 + (2y-1)^2 )mag of z+1 = sqrt((x+1)^2 + y^2) the value of k equal to 2 good luck