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Question 9 answer for the question in a short way but in descriptive form

Rivu , 7 Years ago
Grade 10
anser 1 Answers
Aditya Gupta

Last Activity: 7 Years ago

Write eqn as (x+1)(ax+2x+a)= 0
Now for both roots to be integers, we can write ax+2x+a=0 as
a+2=2/(x+1)
So x= -3,-2,0,1 which gives four values of a as -4,-3,1,0.
So there are four integratl values of a.
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