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Question 31.................................................................

Shivvaiah shivvaiah , 6 Years ago
Grade
anser 1 Answers
Samyak Jain
A \cap B(bar) means only A and A(bar) \cap B means only B.
\therefore there are exactly 9 elements in A which are not in B and 10 elements in B which are not in A.
n(A \cup B) = n(only A) + n(only B) + n(A \cap B) i.e.
24 = 9 + 10 + n(A \cap B)  \Rightarrow  n(A \cap B) = 5. Thus, there are 5 elements in both A and B.
To sum it up, there are (9+5=) 14 elements in A and (10+5=) 15 elements in B in all.
\Rightarrow n(A) = 14  and  n(B) = 15.
We know that n(AxB) = n(A).n(B)  =  (14)(15)  =  210.
Last Activity: 6 Years ago
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