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Grade 12th passAlgebra

Ques 4- on attached file
Answer in the provided answer by you is wrong I guess because you are taking one of the roots as 2alpha and putting it as alpha ?

Question image for Ques 4- on attached file Answer in the provided a
Profile image of UTSAV ROHILLA
6 Years agoGrade 12th pass
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1 Answer

Profile image of Sahil Raj Sigh
6 Years ago
Hi! Hope this answer helps you.
 
Let x2-x+3k=0 be eq-(i) with roots 2a and b, and x2-x+k=0 be eq-(ii) with roots a and c.
For eq (i):-
Sum of roots=2a+b=1 -----eq(iii)
product of roots=2ab=3k----eq(iv)
For eq (ii):-
Sum of roots=a+c=1-----eq(v)
product of roots=ac=k------eq(vi)
 
From eq(iv), k=2ab/3
Putting the value of k in eq(vi),we get
ac=2ab/3
=>c=2b/3
Putting value of c in eq(v),we get
a+2b/3=1
=>3a+2b=3------eq(vii)
Solving eq(iii) and eq(vii) simultaneously, we get
a= -1
b=3
Putting value of a and b in eq(iv), we get
k=-2
 
Ans=k=-2
 

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