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`        Que .xxiiiPlzzzzzzzzzzz solve this mode inequality question............. ..         ......................`
6 months ago

1807 Points
```							this ques can be solved by using a neat “trick”.basically, |a| is less than equal to 1 if and only if a^2 is less than equal to 1. this can be proved simply by noting that a^2 – 1= (|a| – 1)(|a|+1).so we can square both sides in the given inequality.we get (x^2 – 5x+4)^2/(x – 2)^2(x+2)^2 is less than equal to 1.or (x^2 – 5x+4)^2/(x – 2)^2(x+2)^2 – 1 is less than equal to 0or [(x^2 – 5x+4)^2 – (x^2 – 4)^2]/(x – 2)^2(x+2)^2 is less than equal to 0factorise the numerator.x(x – 5/2)(x – 8/5)/(x – 2)^2(x+2)^2 is greater than equal to 0.by wavy curve method, we obtain the final ans asx belongs to [0, 8/5] U [5/2, infinity).kindly approve :)
```
5 months ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions