Prove the following 1.A-(B ∩ C)=(A-B)U(A-C) 2.P(A) ∩ P(B)=P(A ∩ B)

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Riddhish Bhalodia · Answer

1st can be solved by venn diagrams as shown in the figure 2 nd is just common sense LHS says = probability of being in A and probability of being in B = probability of being in A and B = RHS

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Prove the following 1.A-(B ∩ C)=(A-B)U(A-C) 2.P(A) ∩ P(B)=P(A ∩ B)

Prove the following
1.A-(B∩ C)=(A-B)U(A-C)
2.P(A)∩ P(B)=P(A∩ B)

1 Answers

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Prove the following 1.A-(B ∩ C)=(A-B)U(A-C) 2.P(A) ∩ P(B)=P(A ∩ B)

Prove the following 1.A-(B∩ C)=(A-B)U(A-C)2.P(A)∩ P(B)=P(A∩ B)

1 Answers

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Prove the following
1.A-(B∩ C)=(A-B)U(A-C)
2.P(A)∩ P(B)=P(A∩ B)