Polar coordinate of point (-√3,-1) is (2,7π/6)Explain?????
Nitin Kumar , 9 Years ago
Grade 11
Algebra> Polar coordinate of point (-√3,-1) is (2,...
1 AnswersVikas TU
Magnitude = root(3 + 1) = 2
and the argument that is thetha = arctan(1/root3) = 30 degree + 180 degree = 210 degree = 7pie/3
Hence the polar coordinates would be: => (2,7π/6)
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