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Grade: 11
        Polar coordinate of point (-√3,-1) is (2,7π/6)Explain?????
one year ago

Answers : (1)

Vikas TU
6887 Points
							
Magnitude = root(3 + 1) = 2
and the argument that is thetha = arctan(1/root3) = 30 degree + 180 degree = 210 degree = 7pie/3
Hence the polar coordinates would be: =>  (2,7π/6)
one year ago
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