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`        Polar coordinate of point (-√3,-1) is (2,7π/6)Explain?????`
2 years ago

Vikas TU
7037 Points
```							Magnitude = root(3 + 1) = 2and the argument that is thetha = arctan(1/root3) = 30 degree + 180 degree = 210 degree = 7pie/3Hence the polar coordinates would be: =>  (2,7π/6)
```
2 years ago
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