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Grade 10Algebra

plz solve the given question....................
options are xyz,o,abc,1

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Profile image of Prakhar Nigam
8 Years agoGrade 10
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1 Answer

Profile image of Arun
8 Years ago
Here, 
logx/( b - c) =logy/( c - a) = logz/(a - b) =K 

now, 
logx = K(b - c)
alogx = Ka(b - c) 
logx^a = K( ab - ac) 
similarly , 
blogy = Kb( c - a) = K( bc - ab)
logy^a = K( bc- ab)
clogz = K(ac - bc) 
logz^c = K(ac - bc) 
add all terms, 
logx^a + logy^b + logz^c = K(ab - ac + bc -ab + ac - bc) = 0
log{ (x^a)(y^b)(z^c)} = 0
{(x^a)(y^b)(z^c) } = 1 

x^a.y^b.z^c = 1