plz solve the given question....................options are xyz,o,abc,1
Prakhar Nigam , 6 Years ago
Grade 10
Algebra> plz solve the given question................
1 Answers
Arun
Last Activity: 6 Years ago
Here,
logx/( b - c) =logy/( c - a) = logz/(a - b) =K
now,
logx = K(b - c)
alogx = Ka(b - c)
logx^a = K( ab - ac)
similarly ,
blogy = Kb( c - a) = K( bc - ab)
logy^a = K( bc- ab)
logy^a = K( bc- ab)
clogz = K(ac - bc)
logz^c = K(ac - bc)
logz^c = K(ac - bc)
add all terms,
logx^a + logy^b + logz^c = K(ab - ac + bc -ab + ac - bc) = 0
log{ (x^a)(y^b)(z^c)} = 0
{(x^a)(y^b)(z^c) } = 1
x^a.y^b.z^c = 1
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