Grade Select GradeAlgebra
plz can u give me solution of q48 and q49
4 Answers
Akshay
Approved Tutor Answer10 Years agoq49. Sn will be equal to coff. of x in : (1+1/x)n.(1+x)n = ∑nCi*nCi+1 (that is power xi+1 from second bracket multiplied by power xi of first, and i varying from 0 to n-1. (1+1/x)n.(1+x)n = (1+x)2n/xn. Hence Sn(coff. of x = 2nCn+1.Put Sn+1 and Sn and you will get a quardatic equation and n=2 or 4.
Akshay
q48. Assume ((x+1)2-1)n = ∑ nCi (1+x)2n-2i. cofficient of xn will be the series in question.
Expand (x+1)2 in LHS and solve.
ATB.
Akshay
will be the series in question.n. cofficient of x2n-2i (-1)j(1+x)iCn = ∑ n-1)2q48. Assume ((x+1)
Expand (x+1)2 in LHS and solve.
ATB.
Akshay
Add (-1)^j is summation term.
Other Related Questions on algebra
How do you write “the product of 18 and q” as an algebraic expression?
How do you write “the product of 18 and q” as an algebraic expression?
algebra
Last Activity: 2 Years ago