Pls solve the attachment........... ........ . . . ....

f: N ->R 
f(1) = 1 
and f(1) +2f(2) +3f(3) +.... nf(n) , 
for n> 2 , then f(1994) we wnt to find 
f(1) + 2f(2) +3f(3) + .......nf(n) = n(n+1)f(n)
1 = 4f(2) 
f(2) = 1/4 
1+ 2*1/4 +3f(3) = 12f(3)
f(3) = 1/6 
Smilarly 
f(4) = 1/8 
f(1994) = 1/3998