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Pls see the attachment for the question .

Pls see the attachment for the question .

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Grade:12th pass

1 Answers

Nicho priyatham
625 Points
8 years ago
  • by multiplyng Nr and Dr with (1-2isin(x/2))  and equating imagnary part to zero we get the equation 
           2sin2(x/2)+sinx +tan(x/2)=0 
  • 1-cosx +sinx+tanx=0
  • 1+tanx=cosx-sinx
  • (cosx+sinx)/cosx=cosx-sinx
  • (cosx+sinx)/(cosx-sinx)=cosx 
by commponnendo dividendo​ we get 
  • -tanx=tan2(x/2)
since RHS is always positive both should  LHS RHS must be zero  so
  • tan(x/2)=0 and tanx=0
  • x=2n(pie)
 
 
 
 

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