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`        Pls ans 36 in the given attachment of binomial. I can`t get it how to calculate the given expansion`
2 years ago

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137 Points
```							U can write x+1 as (x^1/3)^3 + (1)^3  = a^3 +b^3  now if u apply formula of (a^3 +b^3) u will easily solve out the first part and for the second part u can write x-1 as (x^1/2)^2 - 1^2 and it is a^2 - b^2  then apply the formula and u will get the answer
```
2 years ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions