Flag Algebra> Please tell the answer as soon as possibl...
question mark

Please tell the answer as soon as possible
Regards
............ . .......... ......

Anvita Mahajan , 7 Years ago
Grade
anser 1 Answers
Samyak Jain
Sum of fourth powers of first 2n natural numbers is the sum of fourth powers of first n odd natural numbers
+ sum of fourth powers of first n even natural numbers i.e.
r=12n  r4  =  ∑r=1n (2r – 1)4  +  ∑r=1n (2r)4  or  f(2n) = ∑r=1n (2r – 1)4 + ∑r=1n 16r4 
f(2n) = ∑r=1n (2r – 1)4 + 16 ∑r=1n r4  or  f(2n) = ∑r=1n (2r – 1)4 + 16 f(n)
\therefore r=1n (2r – 1)4  =  f(2n) – 16 f(n).
Hope you understood. Pls approve if you got it.
Last Activity: 7 Years ago
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments