Vandana Kumari11 Years ago2(1/1!+(1+2)/2!+(1+2+3)/3!......)Tn=2n(n+1)/2(n!)=n+1/(n-1)!=n-1+2/(n-1)!=1/(n-2)!+2/(n-1)!S=∑1/(n-2)!+2∑1/(n-1)!=e+2e=3e