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please sooon aspa......................................................................

please sooon aspa......................................................................

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Grade:12

1 Answers

Aditya Gupta
2081 Points
4 years ago
y= (10^x – 10^(-x))/(10^x+10^(-x)) + 1
or y – 1= (10^x – 10^(-x))/(10^x+10^(-x))  
apply componendo and dividendo
(y – 1+1)/(y – 1 – 1)= 10^x/( – 10^(-x))
or y/(2 – y)= 10^2x
or log10 y/(2 – y)= 2x
or x= ½* log10 y/(2 – y)
hence the inverse is ½* log10 x/(2 – x)
kindly approve :)

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