Vaibhav Singh
Last Activity: 8 Years ago
Thanks for asking this question.I Hope my answer could clear your doubt.Given equation is en^2-5n+6 >=0.Here we know that value of e is approx 2.7Hence finding roots n =( 5+√(24e-25) i)/2e and (5 - √(24e -25) i)/2ePlacing these points on each curve____+__●_______________-_________●_____+___ ( 5-√(24e-25)i)/2e (5+√(24e-25)i/2eHence , the interval of solution will be (-Inf, (5-√(24e-25)i)/2e] union [ (5+√(24e-25)i)/2e , Inf) .