Grade 12th passAlgebra
Please solve the problem in the attachment.......... ........ ...... ...... ................
Please solve the problem in the attachment.......... ........ ...... ...... ................
1 Answer
Rajat
fof=f(f(x))
Case 1 if x ≤ 1
fof=f(|x|)
Subcase 1
if |x| ≤ 1, ie. -1≤x≤1
Then fof= ||x|| = |x|
Subcase 2
fof= 2-|x|
If |x| >1 ie. x
Case 2
fof = f(2-x) if x > 1
Subcase 1
fof= |2-x| if (2-x)≤1, ie x≥ 1 ie x>1 { since we already have x>1}
Subcase 2
fof= 2-(2-x)= x is (2-x)>1 ie x 1
Thus fof=. 2-|x| . If x
|x| . If -1≤x≤1
|2-x|. If x>1
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