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Grade: 11

                        

Please solve the following question: The sum 20 C 0 + 20 C 1 + 20 C 2 + …. + 20 C 10 is:

3 years ago

Answers : (1)

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137 Points
							As we know that nC0+ nC1+.....+nCn=2^n,  and nCr=nC(n-r), so by this formula we can easily write        2[20C0+20C1+....+20C9] +20C10= 2^20 so By this u can easily calculate the value and it comes out to be 2^19+ [(20C10)/2] and its value is 616666
						
3 years ago
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