As we know that nC0+ nC1+.....+nCn=2^n, and nCr=nC(n-r), so by this formula we can easily write 2[20C0+20C1+....+20C9] +20C10= 2^20 so By this u can easily calculate the value and it comes out to be 2^19+ [(20C10)/2] and its value is 616666
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