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Please solve Kar dena is problem ko iitians........ which is based on modulus

Amaan Hussain Barbhuyan , 6 Years ago
Grade 11
anser 1 Answers
Ashesh

Last Activity: 6 Years ago

$\left|x^2-1\right|+x+1=0$|x21|+x+1=0









  • $\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}$Subtract x from both sides
    $\left|x^2-1\right|+x+1-x=0-x$|x21|+x+1x=0x
  • $\mathrm{Simplify}$Simplify
    $\left|x^2-1\right|+1=-x$|x21|+1=x
  • $\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}$Subtract 1 from both sides
    $\left|x^2-1\right|+1-1=-x-1$|x21|+11=x1
  • $\mathrm{Simplify}$Simplify
    $\left|x^2-1\right|=-x-1$|x21|=x1
  • $\mathrm{Test\:each\:absolute\:for\:its\:positive\:and\:negative\:ranges}$Test each absolute for its positive and negative ranges
    Show Steps
    $x^2-1\ge\:0\:\mathrm{for}\:x\le\:-1\quad\mathrm{or}\quad\:x\ge\:1,\:\quad\mathrm{therefore\:for}\:x\le\:-1\quad\mathrm{or}\quad\:x\ge\:1\quad\left|x^2-1\right|=x^2-1$x21 0 for x 1    or     x 1,     therefore for x 1    or     x 1    |x21|=x21
    Show Steps
    $x^2-1x210 for 1x1,     therefore for 1x1    |x21|=(x21)
  • $\mathrm{Evaluate\:the\:expression\:in\:the\:following\:ranges:}$Evaluate the expression in the following ranges:
    $xx1, 1 x1, x 1
  • $\mathrm{For:}\:xFor: x1
    $\mathrm{Replace:}\:\left|x^2-1\right|\:\mathrm{with}\:\left(x^2-1\right)$Replace: |x21| with (x21)
    Show Steps
    $x^2-1+x+1=0\quad:\quad x=0,\:x=-1$x21+x+1=0    :    x=0, x=1
    $x=0,\:x=-1$x=0, x=1
  • $\mathrm{For:}\:-1\le\:xFor: 1 x1
    $\mathrm{Replace:}\:\left|x^2-1\right|\:\mathrm{with}\:-\left(x^2-1\right)$Replace: |x21| with (x21)
    Show Steps
    $-\left(x^2-1\right)+x+1=0\quad:\quad x=-1,\:x=2$(x21)+x+1=0    :    x=1, x=2
    $x=-1,\:x=2$x=1, x=2
  • $\mathrm{For:}\:x\ge\:1$For: x 1
    $\mathrm{Replace:}\:\left|x^2-1\right|\:\mathrm{with}\:\left(x^2-1\right)$Replace: |x21| with (x21)
    Show Steps
    $x^2-1+x+1=0\quad:\quad x=0,\:x=-1$x21+x+1=0    :    x=0, x=1
    $x=0,\:x=-1$x=0, x=1
  • $\mathrm{Combine\:the\:ranges}$Combine the ranges
    $\left(x(x1    and    (x=0    or     x=1))    or    (1 x1    and    (x=1    or     x=2))    or    (x 1    and    (x=0    or     x=1))
  • $x=-1$x=1

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