Please solve it.____________________________________________
Arjya Dutta , 4 Years ago
Grade 11
Algebra> Please solve it. ________________________...
3 Answers
Arun
Last Activity: 4 Years ago
Dear student
put y = 0
then you will get
f(0) ( 1 + f(x)) = 0
In case of any difficulty, Please feel free to ask again
Saurabh Koranglekar
Last Activity: 4 Years ago
Dear student
Assume y = 0 to simplify the given equation and determine required
Regards
Aditya Gupta
Last Activity: 4 Years ago
Dear student, above answer is wrong. Correct answer is:
On putting y=0, we see that f(0)(1+f(x))= 0
Since f(x) is non constant, f(0)= 0
Now, we can write
f(x+y)-f(x)= f(y)(1+f(x))
Or Lt y tends to 0 [f(x+y)-f(x)]/y = (1+f(x))*Lt y tends to 0 [f(y)-f(0)]/(y-0)
Or f'(x)= f'(0)(1+f(x))= k(1+f(x))
This differential equation can be easily solved by integrating as
∫f'(x)dx/(1+f(x))= ∫kdx
Or ln(1+f(x))= kx+c
Or f(x)= Ae^kx-1
Put x=0 to get f(0)= A-1
Or A=1
So, f(x)= e^kx - 1
KINDLY APPROVE :))
Provide a better Answer & Earn Cool Goodies
Enter text here...
LIVE ONLINE CLASSES
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Ask a Doubt
Get your questions answered by the expert for free
Enter text here...
Other Related Questions on algebra
Can we divide two vectors? If this is possible then how?
algebra
1 Answer Available
Last Activity: 1 Year ago
How do you write “the product of 18 and q” as an algebraic expression?
algebra
1 Answer Available
Last Activity: 1 Year ago
दहावीच्या आय सी एस इ विद्यार्थ्यांनी पुढे काय करायला पाहिजे
algebra
0 Answer Available
Last Activity: 2 Years ago