Question icon
Grade 11Algebra

Please help me with the Domain of the above mentioned function

Question image for Please help me with the Domain of the above mentio
Profile image of ak
8 Years agoGrade 11
Answers icon

3 Answers

Profile image of Arun
8 Years ago
Dear Aarushi
 
1-x² >0 
x belongs to (-1, 1)
1- sqrt(1 -x²) > 0
1 > sqrt(1 -x²)
x² > 0
x belngs to R..
1 - sqrt (1 - sqrt(1-x²) ) > 0
x belngs to R
Hence
Finally x belngs to (-1, 1)
Profile image of Samyak Jain
8 Years ago
\sqrt{}1 – \sqrt{}1 – \sqrt{}(1 – x2)
Here, terms inside sqr root must be greater than or equal to 0.
\therefore 1 – x\geq 0  or x– 1 \leq 0  or (x+1)(x-1) \leq 0
\epsilon (-1, 1)                           …................(1)
1 – \sqrt{}(1 – x2\geq 0  or  \sqrt{}(1 – x2\leq 1 or 1 – x\leq 1  or x2 \geq 0 , which is always true.
\epsilon R                          ….......................(2)
1 – \sqrt{}1 – \sqrt{}(1 – x2\geq 0   or  1 – \sqrt{}(1 – x2)  \leq 1   or   \sqrt{}(1 – x2\geq 0  
1 – x\geq 0    As i’ve written above    x \epsilon (-1,1)              ...................(3)
Take intersection of (1), (2) & (3) to get 
\epsilon (-1,1), which is the domain of the function
Profile image of Samyak Jain
8 Years ago
Sorry, I made a slight mistake in above answer. the correct answer is below.
\sqrt{}1 – \sqrt{}1 – \sqrt{}(1 – x2)
Here, terms inside sqr root must be greater than or equal to 0.
\therefore 1 – x\geq 0  or x– 1 \leq 0  or (x+1)(x-1) \leq 0
\epsilon [-1, 1]                           …................(1)
1 – \sqrt{}(1 – x2\geq 0  or  \sqrt{}(1 – x2\leq 1 or 1 – x\leq 1  or x2 \geq 0 , which is always true.
\epsilon R                          ….......................(2)
1 – \sqrt{}1 – \sqrt{}(1 – x2\geq 0   or  1 – \sqrt{}(1 – x2)  \leq 1   or   \sqrt{}(1 – x2\geq 0  
1 – x\geq 0    As i’ve written above    x \epsilon [-1,1]              ...................(3)
Take intersection of (1), (2) & (3) to get 
\epsilon [-1,1], which is the domain of the function