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Please help me solve this : If A²=2A-I, then for n≠2, A^n=?

Meghana Bhat , 8 Years ago
Grade 12
anser 1 Answers
Shahid
Given : A2 = 2A -I 
To Find: A= ? ( n ≠ 2)
 
Solution: 
A2 = 2A-I
A= A.A2  = A.(2A – I) = 2A2 – A   = 2 (2A – I) – A   = 4A – 2I – A     =  3A – 2I
Similarly,
A = A. A3 = A.(3A – 2I)   = 3A2  – 2A   = 3 (2A – I) – 2A    = 6A – 3I – 2A      = 4A – 3I
… And so on...
Here , By Symmetry , We Observe That ,
An = nA – (n-1)I
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