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n(F)=38
n(C)=20
n(B)=15
N(FᴒCᴒB)=3
N(FuCuB)=58
n(FuCuB)=n(F)+n(C)+n(B)- n(FᴒC) - n(BᴒC) - n(FᴒB) +n(FᴒBᴒC)
58=38+20+15 - N(FᴒC) - N(BᴒC)-N(FᴒB)+3
58=76 -N(FᴒC) - N(BᴒC)-N(FᴒB)+3
N(FᴒC) - N(BᴒC)-N(FᴒB)=76-58=18
a+3+c+3+b+3=18 (we ascertain this frm venn diagram)
a+b+c+9=18
a+b+c=9
therefore, 9 received medal inexactly 2 of the sports
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