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9 months ago

```							n(F)=38n(C)=20n(B)=15N(FᴒCᴒB)=3N(FuCuB)=58n(FuCuB)=n(F)+n(C)+n(B)- n(FᴒC) - n(BᴒC) - n(FᴒB) +n(FᴒBᴒC)58=38+20+15 - N(FᴒC) - N(BᴒC)-N(FᴒB)+358=76 -N(FᴒC) - N(BᴒC)-N(FᴒB)+3N(FᴒC) - N(BᴒC)-N(FᴒB)=76-58=18a+3+c+3+b+3=18 (we ascertain this frm venn diagram)a+b+c+9=18a+b+c=9therefore, 9 received medal inexactly 2 of the sports
```
9 months ago
```							Dear student Let x get exactly one mrdal and y get 2 medal and as stated 3 men get 3 medals.thereforex+2y+3*3=38+15+20=73x+2y=64alsox+y+3=58= total no. of participantsx+y=55solving we gety=9
```
8 months ago
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