0

Guest

Courses New

Please answer the question as soon as possible thanks

Please answer the question as soon as possible thanks

Question Image
Grade:11

2 Answers

Swarnajit Podder
36 Points
6 years ago
probably (3) is the correct answer.
EXPLANATION:
(x-a)(x-b)+(x-b)(x-c)+(x-c)(x-a)=0
=> 3x2+2(a+b+c)x+(ab+bc+ca)=0
now the roots are equal
discriminant=0
4(a+b+c)2-4*3*(ab+bc+ca)=0
(a+b+c)2-3(ab+bc+ca)=0
a2+b2+c2-ab-bc-ca=0
Swarnajit Podder
36 Points
6 years ago
SORRY....
 
(x-a)(x-b)+(x-b)(x-c)+(x-c)(x-a)=0
=> 3x2-2(a+b+c)x+(ab+bc+ca)=0
now the roots are equal
discriminant=0
4(a+b+c)2-4*3*(ab+bc+ca)=0
(a+b+c)2-3(ab+bc+ca)=0
a2+b2+c2-ab-bc-ca=0

Think You Can Provide A Better Answer ?

Other Related Questions on Algebra

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More