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Please answer me as soon as I am waiting for your help thanks

Please answer me as soon as I am waiting for your help thanks

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Grade:11

1 Answers

Samyak Jain
333 Points
5 years ago
f(x) = \sqrt{} [sin2x] – [cos2x]
For domain of f(x), [sin2x] – [cos2x] \geq 0  i.e. [sin2x] \geq [cos2x]
Compare graphs of [sin2x] & [cos2x] and see for [sin2x] \geq [cos2x]. 
Hence, find the range of f(x), which is 
{ 0 , 1 } . 

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