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Grade: 11
`        Please answer in detail________________________________________________`
one year ago

## Answers : (1)

Arun
24740 Points
```							i) In total there are 3p points, since each of the 3 lines has 'p' points in it. ii) To form a triangle we need 3 non collinear points. So number of triangles that could be formed from 3p points = C(3p, 3) = (3p)*(3p-1)(3p-2)/3! = p(3p-1)(3p-2)/2 iii) Out of these 3p points, each of the 3 lines contain p points. as such no triangle could be formed from each of these 3 set of 'p' points. So number of such triangles = 3*C(p,3) = 3*p*(p-1)*(p-2)/3! = p(p-1)(p-2)/2 iv) Thus number of triangles formed = p(3p-1)(3p-2)/2 - p(p-1)(p-2)/2 This simplifies to: 4p³ - 3p²
```
one year ago
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