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`        Please answer in            detail…………………………………………………....……………`
one year ago

Arun
24510 Points
```							Since x^2+px+1 is a factor of ax^3+bx+c, the other factor should be ax+c. ( by comparing x^3 term and the constant term)So ax^3+bx+c = (x^2+px+1)(ax+c)Comapring the x terms and x^2 terms we getb = pc + a => 2ab = 2pca + 2a^2 …(1)0 = c + pa. Squaring both sides we get0 = c^2 + 2pca +a^2 ……(2)(1) - (2) gives2ab = 2pca + 2a^2 - c^2 - 2pca - a^22ab = a^2 - c^2.
```
one year ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions