P(x) =ax²+bx+c has positive coefficients where a, b, c are in AP. If alpha and beta are integer roots, then (alpha+beta+alpha*beta) =?

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As we know that alpha + beta = -b/a , alpha× beta = c/a and we know that (2b/a)-(c/a)=1. So the answer is( b-a)/a

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P(x) =ax²+bx+c has positive coefficients where a, b, c are in AP. If alpha and beta are integer roots, then (alpha+beta+alpha*beta) =?

P(x) =ax²+bx+c has positive coefficients where a, b, c are in AP. If alpha and beta are integer roots, then (alpha+beta+alpha*beta) =?

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P(x) =ax²+bx+c has positive coefficients where a, b, c are in AP. If alpha and beta are integer roots, then (alpha+beta+alpha*beta) =?

P(x) =ax²+bx+c has positive coefficients where a, b, c are in AP. If alpha and beta are integer roots, then (alpha+beta+alpha*beta) =?

1 Answers

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Other Related Questions on Algebra

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