On the billiard table there are 8 single colored balls and 8 stripped balls . All the balls are different. Arjun wants to take from table 5single colored balls and 6 stripped ball. How many different sets of two balls can he get ?

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ROSHAN MUJEEB · Answer

Dear Student
Use the concept of combination. 5 single can be selected by 8C5 ways since all balls are difference and striped balls can be selected in 8C6 ways similarly. Therefore total combinations are 8C5* 8C6 . Hope you got it .

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On the billiard table there are 8 single colored balls and 8 stripped balls . All the balls are different. Arjun wants to take from table 5single colored balls and 6 stripped ball. How many different sets of two balls can he get ?

On the billiard table there are 8 single colored balls and 8 stripped balls . All the balls are different. Arjun wants to take from table 5single colored balls and 6 stripped ball. How many different sets of two balls can he get ?

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On the billiard table there are 8 single colored balls and 8 stripped balls . All the balls are different. Arjun wants to take from table 5single colored balls and 6 stripped ball. How many different sets of two balls can he get ?

On the billiard table there are 8 single colored balls and 8 stripped balls . All the balls are different. Arjun wants to take from table 5single colored balls and 6 stripped ball. How many different sets of two balls can he get ?

1 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Algebra

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