Observe the following pattern and supply the missing numbers.112 = 121 1012 = 10201101012 = 10203020110101012 = ........................... ...........2 = 10203040504030201

Dear Student

We observe that the square on the number on R.H.S of the equality has an odd number of digits such that the first and last digits both are 1. And, the square is symmetric about the middle digit. If the middle digit is 4, then the number to be squared is 10101 and its square is 102030201.
So, 1010101² =1020304030201
101010101² =10203040505030201

Thanks