#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-5470-145

+91 7353221155

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# Numbers are selected at random, one at a time, from the two digit numbers 00, 01, 02, . . . . . . . . . . . . . . ., 99 with replacement. An even E occurs if only if the product of the two digits of a selected numbers is 18. If four numbers are selected, find probability that the event E occurs at least 3 times.Numbers are selected at random, one at a time, from the two digit numbers 00, 01, 02, . . . . . . . . . . . . . . ., 99 with replacement. An even E occurs if only if the product of the two digits of a selected numbers is 18. If four numbers are selected, find probability that the event E occurs at least 3 times.

7 years ago
Hello Student,
The given numbers are 00, 01, 02, . . . . . . . . . . . . . . . . 99. These are total 100 numbers, out of which the numbers, the product of whose digits is 18, are 29, 36, 63 and 92.
∴ p = P (E) = 4/100 = 1/25 ⇒ q = 1 – p = 24/25
From Binomial distribution
P (E occurring at least 3 times) = P (E occurring 3 times) + P (E occurring 4 times)
4C3 p3 q + 4C4 p4 = 4 x (1/25)3 (24/25) + (1/25)4 = 97/(25)4

Thanks