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Number of postive integral solution of xyz=21600 ?? Please solve this question.....

```
3 years ago

Arun
25768 Points
```							we can write 21600 as a product of its prime factors21600 = 2*2*2*2*2*3*3*3*5*521600 = 25 * 33 * 52hence no. of positive integral solution = (1+2+3+4+5+6)* (1+2+3+4) *(1+2+3) = 21 * 10* 6 = 1260hope it helps
```
3 years ago
Joy Gupta
13 Points
```							   We can use beggers and coins method21600=6^3*10021600=2^5*3^3*5^2.         xyz are beggers so number of solutions=(5+3-1C3-1)(3+3-1C3-1)(2+3-1C3-1)=1260
```
one year ago
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